Question

Afla suma resturilor impartirilor tuturor numerelor naturale x la numărul 3,unde 10 < x < 20

Answer 1

11:3=3 r2
12:3=4 r0
13:3=4 r1
14:3=4 r2
15:3=5 r0
16:3=5 r1
17:3=5 r2
18:3=6 r0
19:3=6 r1

2+0+1+2+0+1+2+0+1=9

Answer 2

11:3=3,2
12:3=4,0
13:3=4,1
14:3=4,2
15:3=5,0
16:3=5,1
17:3=5,2
18:3=6,0
19:3=6,1

Sunt 3 din fiecare nr. din rest

3×(0+1+2)=3×3=9 suma