Question

Află termenul necunoscut din relațiile:a-2 supra 3=unu supra 3,b-unu supra 5=3 supra 5,c-2 supra 8=4 supra 8,d-4 supra 7=3 supra 7,e+unu supra 5=4 supra 5,f+3 supra 6=9 supra 6
Repedeeee,vă rog!!!

Answer 1

Răspuns:

Explicație pas cu pas:

a - 2/3 = 1/3

a = 1/3 + 2/3

a = 3/3

a = 1 intreg

____________

b - 1/5 = 3/5

b = 3/5 + 1/5

b = 4/5

Verific:     4/5 - 1/5 = 3/5

____________

c - 2/8 = 4/8

c = 4/8 + 2/8

c = 6/8

c = 3/4

___________

d - 4/7 = 3/7

d = 3/7 + 4/7

d = 7/7 = 1 (intreg)

_______________

e + 1/5 = 4/5

e = 4/5 - 1/5

e = 3/5

_____________

f + 3/6 = 9/6

f = 9/6 - 3/6

f = ( 9-3)/6

f = 6/6 = 1

Answer 2

$a - \frac{2}{3} = \frac{1}{ 3} \\ a = \frac{1}{3} + \frac{2}{3} = \frac{3}{3} \\ proba \: \frac{3}{3} - \frac{2}{3} = \frac{1}{3}$

$b - \frac{1}{5} = \frac{3}{5} \\ b = \frac{1}{5} + \frac{3}{5} = \frac{4}{5} \\ proba \: \frac{4}{5} - \frac{1}{5} = \frac{3}{5}$

$c - \frac{2}{8} = \frac{4}{8} \\ c = \frac{2}{8} + \frac{4}{8} = \frac{6}{8} \\ proba \: \frac{6}{8} - \frac{2}{8} = \frac{4}{8}$

$d - \frac{4}{7} = \frac{3}{7} \\ d = \frac{4}{7} + \frac{3}{7} = \frac{7}{7} \\ proba \: \frac{7}{7} - \frac{4}{7} = \frac{3}{7}$

$e + \frac{1}{5} = \frac{4}{5} \\ e = \frac{4}{5} - \frac{1}{5} = \frac{3}{5} \\ proba \: \frac{3}{5} + \frac{1}{5} = \frac{4}{5}$

$f + \frac{3}{6} = \frac{9}{6} \\ f = \frac{9}{6} - \frac{3}{6} = \frac{6}{6} \\ proba \: \frac{6}{6} + \frac{3}{6} = \frac{9}{6}$