Question

afla termenul necunoscut din urmatoarele problleme. Metoda mersului invers!

a)[(4xM+5):3+10] :5+5=10

b)[(12+12xM)x10-330]:100=12

Answer 1

a ) [(4*m+5):3+10]:5+5=10
[(4*m+5):3+10]:5=10-5
[(4*m+5):3+10]:5=5
(4*m+5):3+10=5*5
(4*m+5):3+10=25
(4*m+5):3=25-10
(4*m+5):3=15
4*m+5=15*3
4*m+5=45
4*m=45-5
4*m=40
m=40÷4
m=10

b) [(13+12*m)*10-330]÷100=13
[(13+12*m)*10-330]=100*13
(13+12*m)*10-330=1300
(13+12*m)*10=1300+330
(13+12*m)*10=1630
13+12*m=1630÷10
13+12*m=163
12*m=163-13
12*m=150
m=150÷12
m=12,6