Question

afla toate nr naturale care impartite la 7 dau catul 23

Answer 1

1. a + b = 906
(a - b) : b = 5 rest 906

a - b = 5b + 906

 a - 6 b = 906si       | * (- 1)
a + b = 906
-a + 6b = - 906
a + b = 906
7b = 0   =>  b = 0
a = 906

2. a / b = 5 rest 6
a + b + cat + rest = 1217
a = 5b + 6
6b + 6 + 5 + 6 = 1217
6b = 1217 - 17
b = 1200 / 6   b = 200
a = 5 * 200 + 6
a = 1006
3. 205 / 204 = 1 rest 1
206 / 204 = 1 rest 2   s.a.m.d pana la 41616 / 204 = 204 rest 0
4. a / 9 = 1 rest 8
a = 17
5. b / 99 = 5 rest 98
b = 593
6. c / 8 = 24 rest 7
c = 199
7. d / 11 = 7
11 * 7 = 77
8.  e / 2006 = 5 e = 2006 * 5
 e = 10030
10. 23 / 9 = 2 rest 5
2 + 5 = 7 cam asa