Question

Afla toate numerele naturale care impartite la 5, dau catul 7 si restul <5

Answer 1

d : 5 = 7 restul < 5 ⇒ restul = (0, 1, 2, 3, 4)
d = 7 × 5 + 0= 35
d = 7 × 5 + 1 =36
d = 7 × 5 + 2 =37
d = 7 × 5 + 3 =38
d = 7 × 5 + 4 = 39

Answer 2

D:I=C rest R , R<I
D:5=7 rest R , R<5
R € {0,1,2,3,4}

D:5=7 rest 0
D=5×7+0
D=35+0
D=35

D:5=7 rest 1
D=5×7+1
D=35+1
D=36

D:5=7 rest 2
D=5×7+2
D=35+2
D=37

D:5=7 rest 3
D=5×7+3
D=35+3
D=38

D:5=7 rest 4
D=5×7+4
D=35+4
D=39

D € {35,36,37,38,39}