Question

afla toate numerele naturale pare care impartite la 5 dau restul cu 2 mai mare decat catul

Answer 1

                  n : 5 = c  (rest c+2) ⇔ n=5c + c+2

                          ⇒ n=6c+2 iar c+2 < 5 deci c < 3

                                    adica: c = {0;1;2}

                                                  ⇵

                   n = {0*6+2= 2; 1*6+2= 8; 2*6+2= 14} .