Question

afla trei nr nat pare consecutive știind ca adunandu.le cu triplul sumei lor se obține rezultate 528

Answer 1

(x+x+2+x+4)+3(x+x+2+x+4)=528
3x+6+3x+3x+6+3x+12=528
12x=528-6-6-12
x=504:12
x=42
⇒numerele sunt :42,44,46
42+44+46=132
132+3·132=132+396=528

Answer 2

a+(a+2)+(a+4)=s
s+3xs=528
4xs=528
s=528:4
s=132

a+(a+2)+(a+4)=132
a+a+2+a+4=132
3a+6=132 |:3
a+2=44
a=42

Numerele sunt 42, 44 si 46