Question

Afla trei numere pare consecutive stiind ca adunandule cu triplul sumei lor se obtine rezultatul 528.

Answer 1

 nr. a
II nr. a+2
III nr. a+4
(a+a+2+a+4)+3(a+a+2+a+4)=528
(3a+6)+3(3a+6)=528
(3a+6)(1+3)=528
(3a+6)4=528
12a+24=528
12a=528-24
12a=504
a=504:12
a=42 I nr.
42+2=44 II nr.
42+4=46 III nr.

Answer 2

a+b+c=y
y+3y=528
a=x
b=x+2
c=x+4
x+x+2+x+4+3*(x+x+2+x+4)=528
3x+6+3*(3x+6)=528
3x+6+9x+18=528
12x+24=528
12x=504
x=42
x+2=44
x+4=46
verific
42+44+46=132
132*3=396
132+396=528