Question

Afla valoarea lui a început fiecare caz: 10×10+4×(5×5-a)-81÷9×4=92. 100+2×3×(41-a)-64÷8×3×3=7×10

Answer 1

Bună! ⭐

________

$10*10+4*(5 *5- a)-8 1:9 *4 =92 < = >$

$<=> 100+4*(25-a)-9*4=92 <=>$

$<=> 100+100-4a-36=92 < =>$

$<=> 164-4a= 92 < = >$

$<=> -4a=-72 => {\boxed {\mathbf{a=18}}$

________

$100+2*3*(4 1-a)- 64:8*3*3 =7*1 0 <=>$

$<=> 100+6*(41-a)-8*9=70 <=>$

$<=> 100+246-6a-7 2=70 <=>$

$<=> 274-6a=70 <=>$

$<=> -6a=-2 04 => {\boxed{\mathbf{a=34}}$