Question

Află valoarea lui n din egalitatea:
1000-(126×2+906:6-n):2=807



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Answer 1

$1000-(126 \cdot 2+906:6-n):2=807$

$(252+151-n):2= 1000-807$

$(403-n):2= 193$

$403-n= 193 \cdot 2$

$403-n= 386$

$n = 403- 386$

$\implies \bf n=17$