Question

AFLA VALOAREA LUI ''n''din egalitatile; 5xn+245=845 54:n+67x5=344 n:3x8=616 894-n:4=833

Answer 1

5xn+245=845
5xn=845 -245
5xn=600
n=600:5
n=120

54:n+67x5=344
54:n=344 -335
54:n=9
n=54:9
n=6

n:3x8=616
n:3=616:8 
n:3=77
n=77*3
n=231

894-n:4=833
n:4=894-833
n:4=61
n=61*4
n=244