Question

află valoarea lui x din a)[(x-1):100+90]:10-10=0 b)[(x-416:4+2)-5+3]×10=2000 c)160:8+800:5=x:3-480:4 d) [(x+428:4)×2+5]×2-186=800.

Answer 1

a) [(x-1):100+90]:10-10=0|+10
[(x-1):100+90]:10=10|x10
(x-1):100+90=100|-90
(x-1):100=10|x100
x-1=1000|+1
x=1001

b)[(x-416:4+2)-5+3]x10=2000
[(x-104+2)-5+3]x10=2000|:10
(x-104+2)-5+3=200|-3
(x-104+2)-5=197|+5
x-104+2=202|-2
x-104=200|-104
x=96

c)160:8+800:5=x:3-480:4
20+160=x:3-120

d)[(x+428:4)x2+5]x2-186=800
[(x+107)x2+5]x2-186=800|+186
[(x+107)x2+5]x2=986|:2
(x+107)x2+5=493|-5
(x+107)x2=488|:2
x+107=244|-107
x=137

scz ca pe c) l-am lasat asa mai intreabai pe parinti si scz daca am gresit