Question

afla valoarea numarului necunoscut din urmatoarele expesii: 426-(460-10xa)=336,[(58xa-80):25]x64=1280,[(a+54)x4+6]x4-184=800,1100-[(512-144:a)X2]-171=1,[(420:a)x4+24]:4=11

Answer 1

426-(460-10xa)=336
426-460+10xa)=336
10xa=460-426+336
10xa=370
a=370:10
a=37

[(58xa-80):25]x64=1280
[(58xa-80):25]=1280:64
(58xa-80):25=20
(58xa-80)=20x25
(58xa-80)=500
58xa=500+80
58xa=580
a=580:58
a=10

[(a+54)x4+6]x4-184=800
[(a+54)x4+6]x4=800+184
[(a+54)x4+6]x4=984
[(a+54)x4+6]=984:4
[(a+54)x4+6]=246
(a+54)x4=246-6
(a+54)x4=240
(a+54)=240:4
(a+54)=60
a=60-54
a=6

1100-[(512-144:a)X2]-171=1
1100-[(512-144:a)X2]=1+171
1100-[(512-144:a)X2]=172
[(512-144:a)X2]=1100-172
(512-144:a)X2=928
(512-144:a)=928:2
512-144:a=464
144:a=512-464
144:a=48
a=144:48
a=3

[(420:a)x4+24]:4=11
[(420:a)x4+24]=11x4
[(420:a)x4+24]=44
(420:a)x4=44-24
(420:a)x4=20
420:a=20:4
420:a=5
a=420:5
a=84