Question

Află valorile celor trei necunoscute,având relațiile:

{a:b=3(rest 16)
{b:c=2
{a+b+c=475.


{=acoladă

Answer 1

[tex]a=3b+16
c= \frac{b}{2} [/tex]
$a+b+c=475$
$3b+16+b+ \frac{b}{2}$=475
$4b+16+ \frac{b}{2} =475$
$\frac{8b+32+b}{2} =475$
$\frac{9b+32}{2} =475$
9b+32=950
9b=918
b=102
a=3 ori 102+16
a=322
c= 102 supra 3
c=51