Question

Afla valorile lui a si b,daca:
(a+3)x(b-6)=32
Toate posibilitatile va rog mult!!

Answer 1

Stim ca:
1) 32 = 4*8 = 8*4 = -4*-8 = -8*-4
2) 32 = 2*16 = 16*2 = -2*-16 = -16*-2

1.1) 32 = 4*8 => a+3 = 4 => a = 1, b-6 = 8 => b = 14
1.2) 32 = 8*4 => a+3 = 8 => a = 5, b-6 = 4 => b = 10
1.3) 32 = -4*-8 => a+3 = -4 => a = -7, b-6 = -8 => b = -2
1.4) 32 = -8*-4 => a+3 = -8 => a = -11, b-6 = -4 => b = 2

2.1) 32 = 2*16 => a+3 = 2 => a = -1, b-6 = 16 => b = 22
2.2) 32 = 16*2 => a+3 = 16 => a = 13, b-6 = 2 => b = 8
2.3) 32 = -2*-16 => a+3 = -2 => a = -5, b-6 = -16 => b = -10
2.4) 32 = -16*-2 => a+3 = -16 => a = -19, b-6 = -2 => b = 4

Daca nu ai facut la clasa numere negative, atunci renunta la 1.3, 1.4, 2.3 si 2.4.