Question

Afla valuarile celor 3 necunoscute,având relațile:a:b=3rest16 b:c=2 a+b+c=475

Answer 1

a+b+c = 475
a:b = 3 rest 16
a = 3×b+16
b:c = 2 => b =2×c

a |___|___|___|___|___|___|+16
b |___|___|
c |___|

avem 9 segmente egale+16 = 475
475-16 = 459
459:9 = 51 ( un segment)
a = 6×51+16 = 306+16 = 322
b = 2×51 = 102
c = 51

Verificare:
322+102+51= 475

Numerele sunt:
322; 102; 51.