Question

afla x astfel incat nr sa fie in progresie aritmetica 3x-7, 5x-7, x^2+2x-1​

Answer 1

Fie ab,c termenii unei p.a. ⇒ 2b = a+c

2(5x-7) = 3x-7+x²+2x-1

10x-14 = x²+5x-8

x²-5x+6 = 0

delta = 25-24 = 1

x1 = (5+1)/2 = 6/2 = 3

x2 = (5-1)/2 = 4/2 = 2