Question

Aflati 4 numere naturale consecutive stiind ca impartind suma lor la 5 obtinem catul 8 rest 2

Answer 1

a+a+1+a+2+a+3=n
n:5=8 rest 2
n=8x5+2
n=42
a+a+1+a+2+a+3=42
4a=42-6
4a=36
a=36:4
a=9
9+1=10
9+2=11
9+3=12
V: 9+10+11+12=42
    42:5=8 rest 2

Answer 2

d=8x4+2
d=42
42-6=36
36:4=9
9+10+11+12=36