Question

aflati a b c stiind ca sunt proportionale co 0,5,0,2,0 , (3) si a + b + c = 930

Answer 1

rezolvarea este in atasament

Answer 2

{a, b, c} d. p. {0.5 ; 0.2 ; 0.(3)}
a + b + c = 930
$\frac{a}{0.5}$ = $\frac{b}{0.2}$ = $\frac{c}{0.(3)}$ = k
=> a = 0.5k
b = 0.2k
c = 0.(3)k
0.5k + 0.2k + 0.(3)k = 930
0.5 = $\frac{1}{2}$
0.2 = $\frac{1}{5}$
0. (3) = $\frac{1}{3}$
$(\frac{1}{2}) ^{15}$k + $(\frac{1}{5}) ^{6}$k + $( \frac{1}{3}) ^{10}$k = 930$^{30}$
15k + 6k + 10k = 27900
31k = 27900
k = 27900 : 31
k = 900 => a = $\frac{1}{2}$ x 900 = 450
                 b = $\frac{1}{5}$ x 900 = 180
                 c = $\frac{1}{3}$ x 900 = 300
:)