Question

aflati a,b,c, stiind ca sunt proportionale cu 0,5. 0.2. 0.(3)

Answer 1

[tex]\sf a+b+c=930 \\ \{a;b;c\}~d.p~\{0,5;0,2;0,(3)\} \longrightarrow \frac{a}{0,5}= \frac{b}{0,2}= \frac{c}{0,(3)}=k \\ a=0,5k \\ b=0,2k \\ c= \frac{k}{3} \\ 0,5k+0,2k + \frac{k}{3}=930 \\ 0,7k+ \frac{k}{3}=930 \\ \frac{2,1k}{3}+ \frac{k}{3}= \frac{2790}{3} \\ 3,1k=2790 \\ \underline{k=900} \\ a=0,5*900 \\ \boxed{\sf a=450} \\ b=0,2*900 \\ \boxed{\sf b=180} \\ c=930-450-180 \\ \boxed{\sf c=300}[/tex]