Question

aflati ,,a" va rog frumos!!!!!

Answer 1

$a(a + 1)(a + 2) = - 60 \\ ( {a}^{2} + a)(a + 2) = - 60 \\ {a}^{3} + 2{a}^{2} + {a}^{2} + 2a = - 60 \\ {a}^{3} + 3{a}^{2} + 2a = - 60 \\ {a}^{3} + 3 {a}^{2} + 2a + 60 = 0 \\ {a}^{3} + 5 {a}^{2} - 2 {a}^{2} - 10a + 12a + 60= 0 \\ {a}^{2} (a + 5) - 2a(a + 5) + 12(a + 5) = 0 \\ (a + 5)( {a}^{2} - 2a + 12) = 0 \\ \\ a + 5 = 0 \\ a = -5 \\ \\ { a}^{2} - 2a + 12 = 0 \\ delta = 4 - 4 \times 12 < 0 \\ a \:nu \: are \: solutie \: reala \\ \\ \\ solutia \: finala \: a = - 5$