Question

aflati aria totala si volumul unei piramide hexagonale regulate cu latura bazei de 4 cm ,inaltimea de 2 cm si apotema de 4 cm

Answer 1

   
[tex]\displaystyle\\ A_b = 6\times \frac{l^2 \sqrt{3} }{4} = 6\times \frac{4^2 \sqrt{3} }{4} =\boxed{24\sqrt{3}~cm^2}\\\\ A_l = \frac{P_b \times a }{2}= \frac{6l \times a }{2}=\frac{6\times 4 \times 4 }{2}=\boxed{48~cm^2}\\\\ A_t = A_b + A_l = 24\sqrt{3} + 48= \boxed{\boxed{24\Big(\sqrt{3} +2\Big)~cm^2}}\\\\ V= \frac{A_b \times h}{3} =\frac{24\sqrt{3} \times 2}{3} =8\sqrt{3} \times 2= \boxed{\boxed{16\sqrt{3}~cm^3}}[/tex]