Question

aflati aria totala si volumul unei piramide patrulatere regulate cu latura bazei de 24cm si inaltimea de 4radical din 6 cm

Answer 1

Fie M mijlocul laturii BC⇒OM-aptema bazei=24:2=12
                                       ⇒VM-apotema piramidei
In ΔVOM-dreptunghic⇒(teorema lui Pitagora):VM^2=OM^2+VO^2
                                                                          VM^2=12^2+(4√6)^2
                                                                          VM^2=144+96
                                                                           VM^2=240
                                                                            VM=4√15
Aria totala= Aria laterala+A bazei
A laterala= (P bazei×ap):2
               = (96×4√15):2
               =192√15
A bazei=24^2=576
A totala=192√15+576

V=A bazei ×h):3
V=576×4√6):3
V=768√6
Sper ca te-am ajutat! ^..^