Question

aflați aria triunghiului abc ab 6 ac 8 mbac 60​

Answer 1

 

$\displaystyle\bf\\Aria_{\Delta ABC}=\frac{AB\times AC\times sin(m\sphericalangle BAC)}{2}\\\\\\Aria_{\Delta ABC}=\frac{6\times 8\times sin(60^o)}{2}\\\\\\Aria_{\Delta ABC}=\frac{6\times 8\times \dfrac{\sqrt{3}}{2} }{2}\\\\\\Aria_{\Delta ABC}=\frac{6\times 8\times \sqrt{3}}{4}\\\\\\Aria_{\Delta ABC}=6\times 2\times\sqrt{3}\\\\\\\boxed{\bf Aria_{\Delta ABC}=12\sqrt{3}~cm^2}$