Matematică, întrebare adresată de Utilizator anonim, 9 ani în urmă

Aflati c.m.m.d.c si c.m.m.m.c al numerelor: a) 224, 168, 392; b) 1008, 1260, 1134, c) 3240, 5400, 2160; d) 225, 300, 750; e) 1470, 6300, 8820.

Răspunsuri la întrebare

Răspuns de pitiandrei
40
a) 224, 168, 392; c.m.m.d.c  = 2 ^ 3 x 7 = 56  /  
c.m.m.m.c = 2^5 x 3 x 7^2 = 4704
b) 1008, 1260, 1134, c.m.m.d.c  = 2 x 3^2 x 7 = 126 /  c.m.m.m.c = 2^4 x 3^4 x 5 x 7 = 45360
c) 3240, 5400, 2160; c.m.m.d.c  = 2^3 x 3^3 x 5 = 1080  / c.m.m.m.c =2^4 x  3^4 x 5^2 = 32400
d) 225, 300, 750; c.m.m.d.c  = 3 x 5^2 = 75  /  c.m.m.m.c = 2^2 x 3^2 x 5^3 = 4500
e) 1470, 6300, 8820 .c.m.m.d.c = 2 x 3x 5x 7 = 210 /  c.m.m.m.c = 2^2 x 3^2 x 5^2 x 7^2 = 44100
Răspuns de icecon2005
16
a) 224, 168, 392;
c.m.m.d.c=56
c.m.m.m.c
=4704
b) 1008, 1260, 1134
c.m.m.d.c=126
c.m.m.m.c=45360
c) 3240, 5400, 2160;
c.m.m.d.c=1080
c.m.m.m.c
=32400
d) 225, 300, 750;
c.m.m.d.c=75
c.m.m.m.c=4500
e) 1470, 6300, 8820.
c.m.m.d.c=210
c.m.m.m.c=44100





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