Question

Aflati cate numere naturale indeplinesc conditiile:
    
       A)   2xy divizor la 2
    
       B)    x2y  divizor la 5

Answer 1

A) 2xy divizor la 2 inseamna ca y poate lua valorile 2,4,6,8,iar x de la 0 la 9 si avem numerele 200,202,204,206,208,210,212,214,216,218,220,222,224,226,228,230,232,234,236,238,240,242,244,246,248,250,252,254,256,258,260,262,264,266,268,270,272,274,276,278,280,282,284,286,288,290,292,294,296,298


B)x2y divizor la 5 inseamna ca y poate lua valorile 0 si 5 si x oricare de la 1 la 9 deci avem numerele
120,220,320,420,520,620,720,820,920,125,135,145,155,165,175,185,195

Answer 2

210,232,254,276,298...divizor la 2
120,220,320,420,520,620,720,820,920,125,225,325,425,525,625,725,825,925....divizor la 5