Question

aflati catul si restul împartirii numarului 2^n+1•9^n+6^n•3^n+1+37 la 5 unde n este un numar natural

Answer 1

2^n+1•9^n+6^n•3^n+1+37 =
=2^n•2•3^2n+2^n•3^n•3^n•3+37 =
=2^n•3^2n•2+2^n•3^2n•3+37 =
=2^n•3^2n•(2+3)+37

[2^n•3^2n•(2+3)+37 ]: 5 = 2^n•3^2n•(2+3):5 +37:5 =
=2^n•3^2n  + 7    si rest 2