Question

Aflati catul si restul impartirii numarului natural 5, daca:
a)a=24*(*=inmultire)5+3=
b)a=5*37+2=
c)a=2*3*5+1=
d)a=0*1*2*3*4*5+4=
e)a=6*5=
f)a=8*5+5=
g)a=10*5+20*5=
h)a=10*5-4=

Answer 1

“C”=cât
“R”=rest
a)a=24*5+3= 120+5=125 c=25,r=0
b)5*37+2=185+2=187 c=37, r=4
c)a=2*3*5+1=6*5+1=30+1=31 c=6,r=2
d)a=0*1*2*3*4*5+4=0+4=4 c=0, r=8
e)a=6*5=30 c=6, r=0
f)a=8*5+5=40+5=45 c=9, r=0
g)a=10*5+20*5=50+100=150 c=30, r=0
h)a=10*5-4=50-4=46 c=9, r=2