Question

Aflati cel mai mare divizor comun si cel mai mic multiplu comun al numerelor: a) 6 si 12; b) 6, 12 si 18; c) 30, 40 si 50; d) 63, 72 si 81.

Answer 1

a) (6;12)=6 ...[6;12]=12
b)(6;12;18)=6...[6;12;18]=36
c)(30,40,50)=10...[30;40;50]=600
d)(63;72;81)=9...[63;72;81]=4536

Answer 2

a) 6 = 2 x 3
     12= 2 la a 2 x 3
 c.m.m.d.c.= 2 x 3 = 6
c.m.m.m.c. 2 la a 2 x 3 =12
b) 6 = 2 x 3
     12= 2 la a 2 x 3
   18 = 2 x 3 la a 2
c.m.m.d.c =2 x 3 = 12
c.m.m.m.c.= 3 la 2 x 2 la 2 = 36
c)30 = 2 x 3 x 5
40= 2 la 3 x 5
50= 5 la 2 x 2
c.m.m.d.c.=2 x 5 =10
c.m.m.m.c. =2 la 3 x 5 la a 2 x 3 = 600
d) 63 = 3 la 2 x 7
72 = 3 la 2 x 2 la 3
81 =3 la 4
c.m.m.d.c. = 3 la 2 = 9
c.m.m.m.c. = 3 la 4  x 2 la 3 x 7= 81 x 8 x 7= 4536