Question

aflati cel mai mic nr nat care impartit la 15,30,45 da de fiecare data un cat diferit de 0 si restul 3

Answer 1

n : 15 = x rest 3 ==> n = 15x+3
n : 30 = y rest 3 ==> n = 30y+3
n : 45 = z rest 3 ==> n = 45z+3

15 = 3 × 5
30 = 2 × 3 × 5
45 = 3^2 × 5
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c.m.m.m.c = 2 × 3^2 × 5 = 90

n = 90 + 3 = 93 (numarul cautat)


93 : 15 = 6 rest 3
93 : 30 = 3 rest 3
93 : 45 = 2 rest 3