Question

aflati cel mai mic nr natural care impartit la 8,12,15 da restul 7,11 si 14

Answer 1

a÷8=c1 rest 7=>a=8×c1+7

a÷12=c2 rest 11=>a=12×c2+11

a÷15=c3 rest 14 =>a=15×c3+14

Adunam +1 la fiecare relație=>

a+1=8×c1+8=8 (c1+1)

a+1=12×c2+12=12 (c2+1)

a+1=15×c3+15=15 (c3+1)

Aflam cmmmc [8,12,15]

8=2^3

12=2^2×3

15=3×5

[8,12,15]=2^3×3×5=120

a+1=120=>a=119