Question

Aflati cel mai mic numar care impartit la 3,4,5 da resturile 2,3,4 si caturile nenule
Va rog ajutor !

Answer 1

n : 3 = a rest 2 => n = 3a + 2 |+1

n : 4 = b rest 3 => n = 4b + 3 |+1

n : 5 = c rest 4 => n = 5c + 4 |+1


=> n + 1 = 3(a + 1)

=> n + 1 = 4(b + 1)

=> n + 1 = 5(c + 1)


n + 1 = cmmmc [ 3, 4, 5]

n + 1 = 3 × 4 × 5

n + 1 = 60

n = 60 - 1

n = 59 cel mai mic nr natural care respecta conditiile cerintei
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59 : 3 = 19 rest 2

59 : 4 = 14 rest 3

59 : 5 = 11 rest 4