Question

aflati cel mai mic numar care impartit la nr 12; 30 si 48 ,da de fiecare data catul diferit de zero si restul 11

Answer 1

   
[tex]n = numarul~cautat = cmmmc(12; ~30;~ 48) +11 \\ Descompunem~in ~factori~primi: \\ 12=2^2 \times 3 \\ 30 = 2 \times 3 \times 5 \\ 48=2^4 \times 3 \\ n = cmmmc(12; ~30;~ 48) +11 = 2^4 \times 3 \times 5 +11=240+11=\boxed{251} \\ \\ Verificare: \\ 251 : 12 =20~rest~11 \\ 251 : 30 =8~rest~11 \\ 251 : 48=5~rest~11 \\ [/tex]