Question

aflati cel mai mic numar natural care impartit pe rand la 24,36,48 da de fiecare data restul 9 si caturile nenule

Answer 1

n:24=a  9⇒n=24a+9⇒n-9=24a
n:36=b  9⇒n=36b+9⇒n-9=36b
n:48=c  9⇒n=48c+9⇒n-9=48c
24=3x2³
36=2²x3²
48=2⁴x3
c.m.m.m.c=2⁴x3²⇒144
n-9=144⇒n=144+9⇒n=153