Question

aflati cel mai mic numar natural care impartit pe rand la numerele 24,40,36,58, da acelasi rest 5 si caturile nenule

Answer 1

n:24=a 5⇒n-5=24a
n:40=b 5⇒n-5=40b
n:36=c 5⇒n-5=36c
n:58=d 5⇒n-5=58d
aflam  c.m.m.m.c=2³x3²x5x29=10440
24=2³x3
40=2³x5
36=2²x3²
58=2x29
n-5=10440⇒n=10445
plei de la T.I.R(teorema impartirii cu rest