Question

Aflati cel mai mic numar natural care,impartit pe rind la 7,8,9,da resturile 5,6,7.Ajutati-ma va rog mult!!:*:*:*:*

Answer 1

x:7=a rest 5=>x=7a+5
x:8=b rest 6=>x=8b+6
x:9=c rest 7=>x=9c+7
7a+5=8b+6=9c+7|-5
7a=8b+1=9c+2
a=(8b+1)/7=(9c+2)/7
a=b+(b+1)/7=c+2(c+2)/7
7|(b+1) si 7|(c+1)=>c+1=7k=>c=7k-1
8b+6=63k-9+7
b=(63k-8)/8
k=8=>c+1=56=>c=55=>x=9*55+7=502
x=502