Question

Aflati Cifrele a,b,c stiind ca : aa, bc , cb sunt numere prime si aa+bc=cb=aa la puterea a2-a

Answer 1

Nr.prime sunt nr.care au doi divizori( 1 si pe el insusi)
aa+bc+cb=aa^2
aa=11 
aa=11^2
aa=121
11+bc+cb=121
bc+cb=121-11
bc+cb=110
10b+c+10c+b=110
11b+11c=110
11(b+c)=110
b+c=110:11
b+c=10
bc={19,28,37,46,55,64,73,82,91}
cb={19,28,37,46,55,64,73,82,91}