Question

Aflati cifrele nenule a si b stiind ca a < b si a, a (b)+b, b (a)=3, (3)

Answer 1

[tex]\overline{a,a(b)}+\overline{b,b(a)}=3,(3)\Rightarrow \dfrac{\overline{aab}-\overline{aa}}{90}+\dfrac{\overline{bba}-\overline{bb}}{90}=\dfrac{33-3}{9}[/tex]

$110\cdot a+b-11\cdot a+110\cdot b+a-11\cdot b=300$

$100\cdot a+100\cdot b=300$

$a+b=3;\ (a,b \ cifre\ si \ a<b)\Rightarrow a=1;\ \ b=2$