Question

aflați compoziția procentuala pentru acid carbonic

Answer 1

H2CO3

Compozitie procentuala prin masa moleculara

MH2CO3=2+12+3.16=62------>1mol=62g

62 g CO2--------2gH--------12g C----------48gO

100g CO2---------X--------------Y--------------Z

X=100.2:62=3,22 la suta H

Y=100.12:62=19,35 la suta C

Z=100.48:62=77,41 la suta O