Question

Aflati distant dintre punctele
a) A (-1; 4) si B (4; 12)
b) C (4; -3) si D (7; -2)
c) E (7; -5) si F (-5; 11)
d) G (9; -9) si H (-1; -4)

Answer 1

distanta dintre punctele a(x1,y1) si b(x2,y2) se afla dupa formula
$D = \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$
deci:

a) A(-1.4)_B(4,12)
D=$\sqrt{89}$
b)D=$\sqrt{10}$
c)$D= \sqrt{400}=20$
d)$D= \sqrt{100+25} = \sqrt{125}=5 \sqrt{5}$

Answer 2

GH² = (-1-9)² + (-4+9)² =100 + 25 =125 =25·5

GH = 5√5

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$