Question

aflati doua nr naturale stiind ca:
a) au suma 984, catul 3 si restul 4
b) au diferenta 725 catul 9 si restul 5

Answer 1

[tex]a+b=984 \\ a:b=3r4=\ \textgreater \ a=3b+4 \\ 3b+4+b=984 \\ 4 b=984-4 \\ b=245 \\ a=3*245+4=739 \\ \\ a-b=725 \\ a:b=9r5=\ \textgreater \ a=9b+5 \\ 9b+5-b=725 \\ 8b=725-5 \\ b=720:8=90 \\ a=9*90+5=815 [/tex]

Answer 2

a+b=984
a:b=3 r 4 
a = 3b + 4
3b+ 4 + b= 984
4b= 984:4
b=245
a=3*245+4
a=739

a-b=725
a:b=9 r 5
a= 9b+5
9b+5-b=725
8b=725:5
b= 90
a= 9*90+5
a=815