Question

Aflati doua nr naturale stiind ca unul este mai mare decat celalalt cu 33 iar daca impartim triplul sumei lor la dublui diferentei lor obtinem catul 2 si restul 57 . 

Answer 1

a=b+33
3(a+b):2(a-b)=2r57
3(b+33+b):2(b+33-b)=2r57
3b+99+3b:2b+66-2b=2r57
6b+99=2(2b+66-2b)+57
6b+99=4b+132-4b+57
6b-4b+4b=132-99+57
6b=90
b=90:6
b=15
a=15+33
a=48

Answer 2

x=y+33
3(x+y):2(x-y)=2 rest57
3(x+y)=2x2(x-y)+57
3(x+y)=4(x-y)+57
3(y+33+y)=4(y+33-y)+57
3(2y+33)=4x33+57
6y+99=132+57
6y=90
y=90/6=15
x=15+33=48