Question

aflati doua numere care au suma 121, stiind ca numarul MARE impartit la cel mai mic da catul 5 si restul 15.

VA ROG URGENT !!!

Answer 1

a+b=121

a:b=5 rest 13 conform teoremei de impartire cu rest⇒a=5b+13

(5b+13)+b=121

6b=121-13⇒6b=108⇒b=108:6⇒b=18

b=18, a=5b+13=90+13=103

b = 18  si  a = 103

verificare

a+b=121⇒103+18=121

Answer 2

a+b=121
a:b=5 rest 13⇒a=5xb+13
5xb+13+b=121
6b=121-13
6b=108
b=108:6
b=18 numarul mic
a=5x18+13=90+13=103 numarul mare

Verific: 103+18=121 (suma)
103:18=5 rest 13