Question

Aflati doua numere ce au diferenta 9,75 iar unul din numere este de 1,5 ori mai mare decat celalalt.

Answer 1

a-b=[tex] \frac{975}{100} [/tex]
a=$\frac{15}{10} *b$
$\frac{15}{10}*b-b= \frac{975}{100}$   (se amplifica b cu 10 si se obtine) 
$\frac{15b-10b}{10} = \frac{975}{100}$
$\frac{5b}{10} = \frac{975}{100}$
100*5b=975*10
$5b= \frac{975*10}{100} = \frac{195}{2}$
$b= \frac{195}{2} : 5 = \frac{195}{2} * \frac{1}{5} = \frac{39}{2}$
$a= \frac{15}{10} * \frac{39}{2} = \frac{585}{20} = \frac{117}{4}$

Verificare: 39/2 = 19.5 si 117/4=29.25; 29.25-19.5=9.75