Question

Aflati doua numere naturale stiind ca suma lor este 102,iar impartind numarul mare la cel mic abotinem catul 2 si restul 12

Answer 1

a+b=102

a:b=2+12

a=2b+12

b+2b+12=102

3b+12=102

3b=90

b=30

a=30 x 2+12=60+12=72

a=72

Answer 2

a+b=102 ==> a:b=2 rest 12 => a=b*2+12 => a=2b+12 ==> 2b+12+b=102 ==> 3b=102-12 ==> 3b= 90 ==> b=90/3 ==> b=30 a+30=102 a=102-30 a=72