Question

aflati fractia ordinara ireductibila rezultata din fractia 2+4+6+ ...+100/ 3+6+9+...+150 prin simplificarea acesteia.

Answer 1

2+4+6+......+100/3+6+9+......+150= 2(1+2+3+.....50)/3(1+2+3+.....+50) = 2/3
am simplificat prin (1+2+3+.....+50) .