Question

aflati intreitul sumei numerelor a,b,c,determinate din expresiile:
a={89+571-11x[2404:(9x3-23:1)-548]}x39
b=(71-3x4)+300:[124-(bx8+2x0)x1]=74
c este diferenta dintre 1000 si catul numerelor a si b
multumesc

Answer 1

a={89+571-11x[2404:(9x3-23:1)-548]}x39=
={660-11x[2404:(27-23)-548]}x39=
=[660-11x(2404:4-548)]x39=
=[660-11x(601-548)]x39=
=(660-11x53)x39=
=(660-583)x39=
=77x39=3003

(71-3x4)+300:[124-(bx8+2x0)x1]=74
(71-12)+300:(124-8b)=74
59+300:(124-8b)=74
300:(124-8b)=74-59
300:(124-8b)=15
124-8b=300:15
124-8b=20
8b=104
b=13

c=1000-a:b=1000-3003:13=1000-231=769
(3003+13+769)x3=3785x3=11355