Question

Aflați m€R, cu |(m-3)i+(m+1)j|=4
Urgent

Answer 1

Răspuns:

Explicație pas cu pas:

$\sqrt{(m-3)^{2}+(m+1)^{2}} =4,~(m-3)^{2}+)m+1)^{2}=16,~m^{2}-6m+9+m^{2}+2m+1=16,~2m^{2}-4m-6=0,~m^{2}-2m-3=0,~m^{2}-2m+1=4=0,~(m-1)^{2}-2^{2}=0,~(m-1-2)(m-1+2)=0,~(m-3)(m+1)=0~deci~m=-1;~m=3$