Question

aflati media aritmetica a numerelor 1 supra 6 ,2 supra 9 ,3 supra 4
3 supra 7 ,1 supra 5 ,2 si 6
1,2 ;0,15;3,4
1,(5);0,1(5);1,5

Answer 1

(1/6+2/9+3/4)/3=[(6+8+27)/36]/3=41/108=0,37(962)

(3/7+1/5+2/6)/3=[(90+42+70)/210]/3=(202/210)/3=101/315=0,32(063492)

(1,2 +0,15+3,4)/3=4,75/3=1,58(3)

1,(5)=(15-1)/9=14/9
0,1(5)=(15-1)/90=14/90
1,5 =15/10

(1,(5)+0,1(5)+1,5 )/3=
=14/9+14/90+15/10)/3=
=(140/90+14/90+135/90)/3=
=(140/90+14/90+135/90)/3=
=289/270=1,0(703)