Question

aflati media aritmetica a numerelor x si y in urmatoarelor cazuri: a)x=502,7:10² si y=0,943x10² b)x=195,3:10²si y=0,006x10² VA ROG MULT DAU COROANA

Answer 1

a ) x=5.027 y= 94.3 med.arit. = 5.027+94.3 : 2=99.327:2=46.6635 b) x=19530 y=0.6 Med.arit.= 19530+0.6:2=19530.6:2 =9675.3

Answer 2

a)x=502,7:(10x10)=502,7:100=5
y=0,943x(10x10)=0,943x100=94,3
94,3x5=471,5
b)x=195,3:(10x10)=195,3:100=1,95
y=0,006x(10x10)=0,006x100=0,6
1,95x0,6=1,17